X^2-15x-168=0

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Solution for X^2-15x-168=0 equation:



X^2-15X-168=0
a = 1; b = -15; c = -168;
Δ = b2-4ac
Δ = -152-4·1·(-168)
Δ = 897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{897}}{2*1}=\frac{15-\sqrt{897}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{897}}{2*1}=\frac{15+\sqrt{897}}{2} $

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